When we reduce by the common denominator, this does not complete the division operation, division must be applied to both the factor and the coefficient. Division is sustained.
* In the notation above, a multiplier of one is always implied for any number. For example, x == 1x.
==Correct solution written as a fraction ==
In the denominator, both the coefficient and the factor must be divided in the following manner.
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6
----
2(1+2)
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<br/>
=
<br/>
</div>
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3
----
(1+2)
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<br/>
=
<br/>
</div>
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3
----
3
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<br/>
= 1
<br/>
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== The calculator problem ==