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'''Solution:'''
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6
----
2(1+2)
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<br/>
=
<br/>
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3
----
(1+2)
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<br/>
=
<br/>
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3
----
3
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<br/>
= 1
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<!--
As we can see, we cannot add an EXPLICIT operator to 6÷2(1+2) without maintaining the IMPLICIT relationship that was stated with IMPLIED multiplication. 6÷2(1+2) == 6÷(2*(1+2)).
-->
==The equation is not ambiguous ==