Changes

Standing alone, 6 will always equal 6 and 2(1+2) will also always equal 6, so dividing these two terms will always equal 1. We would not write 2(a+b) as (2(a+b)), nor would we re-write the given equation as 6÷2*(a+b). Granted, the [https://www.wyzant.com/resources/blogs/14831/the_obelus_for_division obelus (÷)] is an archaic symbol for division, but this is not a postgraduate level equation, this is middle-school level math.

We would not write 2(1a+b) as (2(a+b)) is understood to be a function, placing this function anywhere in a larger equation must always resolve to nor can we re-write the same value. The given equation, as 6÷2*(1a+2b)=? is illustrative . We can however, rewrite the expression to why include an implicit multiplier if we cannot substitute explicit multiplication take care to maintain the grouping with additional bracketing for implied multiplicationuse with calculators and programming languages 6÷(2*(a+b)). Granted, in other wordsthe [https://www.wyzant.com/resources/blogs/14831/the_obelus_for_division obelus (÷)] is an archaic symbol for division, 6÷2computers use the forward slash for division 6/(1+2) is not equal to 6÷2*(1a+2b)).

* 2(1+2) is understood to be a function, placing this function anywhere in a larger equation must always resolve to the same value. The equation, 6÷2(1+2)=? is illustrative to why we cannot substitute explicit multiplication for implied multiplication without additional bracketing, in other words, 6÷2(1+2) is not equal to 6÷2*(1+2). {{Quote|text='''''Implied multiplication ''' has a higher priority than explicit multiplication to allow users to enter expressions, in the same manner as they would be written.''<br/>